View Android Source Code in Eclipse
Recently, I have been hacking around with Android a lot, and I think it’s awesome.
Unfortunately, the Android SDK does not come with source code, and sometimes the docs are not so great, yet. Being an open source project, the Android sources are available online, but they are not very easy to access from Eclipse. For one, the source files are sometimes difficult to find as they are distributed over many individual Git repositories, and then I am not always online.
Integrating source files into Eclipse is usually quite easy, but the Android Eclipse plugin (ADT) does not allow to modify the Java Source Attachment of android.jar in the Android Library. Fortunately, you only have to find out what the default location for source code is. Eric Burke nicely describes how to find that out.
Long story short: Android source code needs to be placed in a sources
subdirectory of the Android SDK. Here is what you need to do:
- Get the Android source code (install repo, repo init, repo sync)
- Move all Java sources into a
sources
subdirectory of the Android SDK
Step 2 sounds easier than it is. There are a lot of Java files in the Android
sources, and they are sprinkled all over the place. Eclipse, however, needs the
source files in a standard Java source directory structure: The path of a source
file needs to match its package name. To simplify this task, I have written a
short Python script that recursively searches for Java files and packs them into
a ZIP file. Unpack that source file into a sources
subdirectory of the Android
SDK. Enjoy:
from \_\_future\_\_ import with\_statement # for Python < 2.6
import os
import re
import zipfile
# open a zip file
DST\_FILE = 'sources.zip'
if os.path.exists(DST\_FILE):
print DST\_FILE, "already exists"
exit(1)
zip = zipfile.ZipFile(DST\_FILE, 'w', zipfile.ZIP\_DEFLATED)
# some files are duplicated, copy them only once
written = {}
# iterate over all Java files
for dir, subdirs, files in os.walk('.'):
for file in files:
if file.endswith('.java'):
# search package name
path = os.path.join(dir, file)
with open(path) as f:
for line in f:
match = re.match(r'\\s\*package\\s+(\[a-zA-Z0-9\\.\_\]+);', line)
if match:
# copy source into the zip file using the package as path
zippath = match.group(1).replace('.', '/') + '/' + file
if zippath not in written:
written\[zippath\] = 1
zip.write(path, zippath)
break;
zip.close()